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CBSE 10

CBSE 10 Probability: Crack the Code of Chance (10 Examples)

May 7, 2024

Welcome to the fascinating world of probabilities - a branch of mathematics that allows people to predict and understand uncertain events. Journey through the enchanting realm of probability and equip yourself with the tools to crack the code of chance. Whether you are a student preparing for your board exams or someone eager to delve into the intricacies of this captivating subject, this blog post is tailor-made for you.

Probability is all around us, influencing people’s everyday decisions and shaping the world. From weather forecasts and stock market predictions to game strategies and risk assessment, probabilities play a vital role in various aspects of life and science. As you embark on this journey of mastering probabilities, begin with a comprehensive introduction to the key concepts and principles that form the foundation of this mathematical wonder.

Understanding probability

At its core, probability deals with the likelihood of an event occurring. The probability of an event is expressed as a number between 0 and 1, where 0 represents an impossible event, and 1 signifies a certain event. For example, when flipping a fair coin, the probability of getting heads is 0.5 (or 1/2) since there are two equally likely outcomes - heads and tails.

The basic principles

  • Theoretical probability: This is the probability of an event based on theoretical reasoning. For instance, in a standard deck of 52 playing cards, the probability of drawing an Ace is 4/52 since there are four Aces in the deck.
  • Experimental probability: This involves conducting real-world experiments to determine the probability of an event. For instance, rolling a fair six-sided die multiple times and recording the number of times a specific number appears will give us the experimental probability.

Probability of compound events

  • Independent events: Events are independent when the occurrence of one event does not affect the occurrence of another. For example, flipping a coin and rolling a die are independent events.
  • Dependent events: Events are dependent when the occurrence of one event affects the occurrence of another. For example, drawing two marbles from a bag without replacement is a dependent event.

Probability distributions

Probability distributions help us understand the likelihood of different outcomes in a given scenario. For instance, a binomial distribution is used to calculate the probability of a specific number of successful outcomes in a fixed number of trials, each with the same probability of success.

Complementary events

The probability of an event happening (P) plus the probability of the event not happening (1 - P) always adds up to 1. These complementary events help us analyze scenarios more comprehensively.

Visual representation

Probability can be visually represented using tools like Venn diagrams, tree diagrams, and probability charts. These aids provide a clear and intuitive understanding of complex probability problems.

Real-world applications

Probabilities find applications in various fields, including:

  • Weather forecasting: Meteorologists use probability to predict the likelihood of rain, storms, or sunny days.
  • Sports strategies: Coaches and players use probabilities to devise winning game strategies in sports like cricket, football, and basketball.
  • Risk assessment: In insurance and finance, probabilities are used to assess risk and make informed decisions.
  • Medical studies: Probability is essential in clinical trials and medical research to evaluate the effectiveness of treatments.

In the next section, dive deeper into each concept, explore solved examples, and tackle challenging probability problems. Understanding probabilities not only enhances your problem-solving skills but also equips you with a valuable tool to make well-informed decisions in various life situations.

Top HOTs for CBSE 10 Probability

Question 1:

In a jar, 25 green candies and 30 yellow candies are placed. If a candy is drawn randomly from the jar, what is the probability of selecting a yellow candy?

✅ Solution:

  1. The total number of candies in the jar is 25 (green) + 30 (yellow) = 55 candies.
  2. We want to find the probability of selecting a yellow candy.
  3. The number of favorable outcomes (yellow candies) is 30.
  4. Using the formula for probability:
\[ \begin{aligned} \text{Probability of selecting a yellow candy} & = \frac{\text{Number of yellow candies}}{\text{Total number of candies}} \\ & = \frac{30}{55} \\ & = \frac{6}{11}. \end{aligned} \]

Question 2:

You choose a card at random from a deck of 52 playing cards. What is the probability of selecting a card that is not a face card (jack, queen, king) when each card in the deck has an equal chance of being drawn?

✅ Solution:

  1. A standard deck of playing cards contains 52 cards.
  2. Face cards include jacks, queens, and kings, which each have four cards in the deck, making a total of \(3 \times 4 = 12\) face cards.
  3. There are \(52 - 12 = 40\) non-face cards in the deck.
  4. Using the formula for probability:
\[ \begin{aligned} \text{Probability of selecting a non-face card} & = \frac{\text{Number of non-face cards}}{\text{Total number of cards}} \\ & = \frac{40}{52} \\ & = \frac{10}{13}. \end{aligned} \]

Question 3:

Two coins are flipped simultaneously, and you observe their outcomes (heads or tails). Determine the probability that their outcomes is not equal to two heads when both coins are equally likely to land on either side.

✅ Solution:

  1. When flipping two coins, there are four possible outcomes: HH (heads-heads), HT (heads-tails), TH (tails-heads), and TT (tails-tails).
  2. We want to find the probability that the outcome is not equal to two heads (HH).
  3. From the four possible outcomes, only three of them have a product that is not equal to two heads: HT, TH, and TT.
  4. Since each outcome is equally likely, the probability of getting HT, TH, or TT is \( \frac{3}{4} \).

So, the probability that the outcome is not equal to two heads is \( \frac{3}{4} \).

Question 4:

You are given a deck of cards, and each card has a unique number from 1 to 100 (each number appears on one and only one card). A card is drawn randomly from the deck. What is the probability that the number on the drawn card is a multiple of 3?

✅ Solution:

  1. To find the numbers that are multiples of 3 within this range, we need to identify the multiples of 3: 3, 6, 9, ..., 99.
  2. Calculating the count of multiples of 3:
  3. \[ \begin{aligned} \text{Count of multiples of 3} & = \frac{\text{Highest multiple (99)} - \text{Lowest multiple (3)}}{3} + 1 \\ & = \frac{96}{3} + 1 \\ & = 32 + 1 \\ & = 33. \end{aligned} \]
  4. There are a total of 33 multiples of 3 within the range of numbers, each of which appears on one and only one card.
  5. Using the formula for probability:
\[ \begin{aligned} \text{Probability of drawing a multiple of 3 card} & = \frac{\text{Number of multiples of 3}}{\text{Total number of cards}} \\ & = \frac{33}{100}. \end{aligned} \]

Question 5:

A spinner is divided into six equal sections: red, blue, green, yellow, orange, purple. What is the probability of landing on a primary color (red, blue, or green)?

✅ Solution:

  1. The spinner has six equal sections.
  2. We want the probability of a primary color (red, blue, green).
  3. Three primary colors: red, blue, green.
  4. Total possible outcomes: 6.
  5. Using the probability formula:
\[ \begin{aligned} \text{Probability of landing on primary color} & = \frac{\text{Number of primary colors}}{\text{Total possible outcomes}} \\ & = \frac{3}{6} \\ & = \frac{1}{2}. \end{aligned} \]

Question 6:

You flip a fair coin four times. What is the probability that you won't get any tails (i.e., all outcomes are heads)?

✅ Solution:

  1. When flipping a fair coin, there are two possible outcomes: heads (H) or tails (T).
  2. We want to find the probability of getting all heads (HHHH) in four flips.
  3. Since each flip is independent and has a probability of \( \frac{1}{2} \) for heads, the probability of getting all heads in four flips is \( \left(\frac{1}{2}\right)^4 = \frac{1}{16} \).

So, the probability of not getting any tails (all outcomes are heads) is \( \frac{1}{16} \).

Question 7:

Visualize a box with tickets numbered from 1000 to 5000. If a ticket is randomly selected from the box, what is the probability that the number on the ticket is divisible by 7?

✅ Solution:

  1. Range of ticket numbers: 1000 to 5000.
  2. Multiples of 7 in this range: 1001, 1008, 1015, ..., 4998.
  3. Highest multiple: 4998.
  4. Lowest multiple: 1001.
  5. Calculating the count of these multiples:
  6. \[ \begin{aligned} \text{Count of multiples of 7} = \frac{\text{4998} - \text{1001}}{7} + 1 & = \frac{3997}{7} + 1 \\ & = 571. \end{aligned} \]
  7. There are a total of 571 numbers in the range that are divisible by 7.
  8. Using the probability formula:
\[ \begin{aligned} \text{Probability of drawing a number divisible by 7} & = \frac{571}{4001}. \end{aligned} \]

Question 8:

In a box, there are 6 red marbles, 4 blue marbles, and 5 green marbles. Two marbles are drawn at random without replacement. What is the probability that the first marble drawn is red and the second marble drawn is blue?

✅ Solution:

  1. Total marbles: \(6\) red + \(4\) blue + \(5\) green = \(15\) marbles.
  2. We want the probability of drawing a red marble first and then a blue marble second.
  3. Probability of drawing red first: \(\frac{6}{15}\).
  4. After 1st draw, \(14\) marbles left.
  5. Probability of drawing blue second: \(\frac{4}{14}\).
  6. Using multiplication rule:
\[ \begin{aligned} \text{Probability of red then blue} & = \text{Probability of red} \times \text{Probability of blue} \\ & = \frac{6}{15} \times \frac{4}{14} \\ & = \frac{8}{105}. \end{aligned} \]

Question 9:

In a bag, there are marbles labeled with numbers from 50 to 600. A marble is drawn at random from the bag. What is the probability that the number on the drawn marble is not a multiple of 5?

✅ Solution:

  1. Marble numbers range: 50 to 600.
  2. Count multiples of 5 within range:
  3. \[ \begin{aligned} \text{Highest multiple of 5} &= 595 \\ \text{Lowest multiple of 5} &= 50 \\ \text{Number of multiples of 5} &= \frac{\text{Highest - Lowest}}{5} + 1 \\ &= \frac{595 - 50}{5} + 1 \\ &= 110. \end{aligned} \]
  4. Count non-multiples of 5:
  5. \[ \begin{aligned} \text{Count of non-multiples of 5} &= \text{Total numbers} - \text{Number of multiples of 5} \\ &= 600 - 110 \\ &= 490. \end{aligned} \]
  6. Using probability formula:
\[ \begin{aligned} \text{Probability of drawing a non-multiple of 5} &= \frac{\text{Count of non-multiples}}{\text{Total marbles}} \\ &= \frac{490}{551} \\ &= \frac{10}{11}. \end{aligned} \]

Question 10:

Imagine flipping a coin and rolling a six-sided die at the same time. What is the probability that either the coin lands heads up or the die shows an odd number?

✅ Solution:

  1. When flipping a coin, outcomes are heads (H) or tails (T).
  2. Rolling a die, outcomes are 1, 2, 3, 4, 5, or 6.
  3. Probability of coin heads: \( \frac{1}{2} \).
  4. Probability of odd die number: \( \frac{1}{2} \).
  5. Probability of coin heads and odd die number: \( \frac{1}{4} \).
  6. Using the Inclusion-Exclusion Principle:
\[ \begin{aligned} \text{Probability of coin heads or odd die number} & = \frac{1}{2} + \frac{1}{2} - \frac{1}{4} \\ & = \frac{3}{4}. \end{aligned} \]

FAQs

1. What is probability in Maths Class 10?

In Maths Class 10, probability is a branch of mathematics that deals with the likelihood of an event occurring. It is represented as a number between 0 and 1, where 0 indicates an impossible event, and 1 signifies a certain event. Students learn to calculate probabilities of different events using various techniques and concepts.

2. How to solve probability?

Solving probability involves understanding the basic principles and techniques. Here's a step-by-step guide:

  1. Define the event: Clearly identify the event for which you want to find the probability.
  2. Identify outcomes: Determine the total number of possible outcomes in the given scenario.
  3. Count favorable outcomes: Count the number of outcomes that fulfill the conditions of the desired event.
  4. Calculate probability: Divide the number of favorable outcomes by the total number of possible outcomes.

3. What is an example of probability in 10th class?

An example of probability in Class 10 involves flipping a fair coin. The probability of getting heads is 0.5 (or 1/2) since there are two equally likely outcomes - heads and tails. Another example could be rolling a standard six-sided die. The probability of rolling a 3 is 1/6, as there is one favorable outcome (rolling a 3) out of the six possible outcomes.

4. What are the basics of probability?

The basics of probability in Class 10 include:

  • Defining probability as the likelihood of an event occurring.
  • Representing probability as a number between 0 and 1.
  • Understanding the difference between theoretical and experimental probability.
  • Identifying independent and dependent events.
  • Using probability distributions to analyze different outcomes.
  • Employing visual aids like Venn diagrams and tree diagrams for better understanding.

Conclusion

In conclusion, probabilities are a fascinating field of mathematics that allows us to navigate the uncertainties of life and make informed decisions. As you continue to delve into the enchanting world of probabilities, remember that practice and understanding key concepts are the keys to mastery. Whether you're a student preparing for your board exams or an enthusiast eager to explore this captivating subject, Aha AI provides a comprehensive platform to sharpen your skills and excel in probability. So, take the next step on your journey to crack the code of chance by visiting Aha AI's website.

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